The Babson Task

(1) Drumare,P - [#5] Memorial Seneca, 1980 1.Rf2 cxb1Q [ 1...cxb1N 2.fxg8N Na3+ 3.R4xa3 exd3 4.Nf6 Kc3 5.Ne4# ; 1...cxb1B 2.fxg8B Bxd3 3.Bd5 Bc2 4.Bxe4+ Bd3 5.Rxd3# ; 1...cxb1R 2.fxg8R exd3 3.Rg5 Nc2 4.Rg3+ Ne3 5.Bxe3# ] 2.fxg8Q Qc2 3.dxe4+ Qd3 4.Qg7 Qxd8 5.Qc3# 1-0

(2) Yarosh,L - [#4] Shakhmatny v. SSSR, 1983 1.Rxh4 cxb1Q [ 1...cxb1N 2.axb8N Nxd2 3.Nc6+ Kc3 4.Rc1# ; 1...cxb1B 2.axb8B Be4 3.Bxf4 Bxh1 4.Be3# ; 1...cxb1R 2.axb8R Rxb2 3.Rb3 Kxc4 4.Rxf4# ] 2.axb8Q Qxb2 [ 2...Qe4 3.Qxf4 Qxf4 4.Rxf4# ] 3.Qb3 Qc3 4.Qxc3# 1-0

(3) Yarosh,L - [#4] Shakhmatny v. SSSR, 1st Prize, 1983 1.a7 axb1Q [ 1...axb1N 2.axb8N Nxd2 3.Qc1 Ne4 4.Nc6# ; 1...axb1B 2.axb8B Be4 3.Bxf4 Bxa8 4.Be3# ( 4.Be5# ) ; 1...axb1R 2.axb8R Rxb2 3.Rxb3 Kxc4 4.Qa4# ] 2.axb8Q Qxb2 [ 2...Qe4 3.Qxf4 Qxf4 4.Rxf4# ] 3.Qxb3 Qc3 4.Qaxc3# 1-0

(4) Yarosh,L - [#4] Themes-64, 1st Prize, 1983 In his most perfect version the incredible Yarosh has even got rid of the mating dual in the bishop line. He dedicated this problem to P. Drumare. 1.Nxc3 c1Q [ 1...c1R 2.exd8R! Rxc3 3.Nxf6 Kxf6 4.Bxc3# ; 1...c1B 2.exd8B! Bxe3 3.Rc4 Kd6 4.Ne4# ; 1...c1N 2.exd8N! Nb3+ 3.Kb6 Nxa1 4.Nf7# ] 2.exd8Q! Qxc3 [ 2...Qxe3 3.Rc4 Qe4 ( 3...Qxe2 4.Nxe2# ) ] 3.Nxf6 Qxb2 [ 3...Qd4 4.Bxd4# ] 4.Qxb2# 1-0